Answer:
there is no sufficient evidence to prove that viscosity is not 3000
Step-by-step explanation:
Let's state the hypothesis.
Null hypothesis; H0: μ = 3000
Alternative hypothesis; μ ≠ 3000
The sample mean is;
x = (2781 + 2900 + 3013 + 2856 + 2888)/5 = 2887.6
Standard deviation σ = √variance = √[(2781 - 2887.6)² + (2900 - 2887.6)² + (3013 - 2887.6)² + (2856 - 2887.6)² + (2888 - 2887.6)²)(1/(5 - 1))]
σ = √((1/4)(11363.56 + 153.76 + 15725.16 + 998.56 + 0.16)
σ = 84.026
Formula for test statistic is given as;
t = (x - μ)/σ
t = (2887.6 - 3000)/84.026
t = -1.338
From online p-value calculator from t value attached, using DF = 5 - 1 = 4, two tail and a significance level of 0.05,we have;
The p-value is 0.251896.
This is greater than the significance level of 0.05.
Thus, we will fail to reject the null hypothesis and conclude that there is no sufficient evidence to prove that viscosity is not 3000
