Answer:
See explanation
Explanation:
For this question, we must bear in mind that in the isomers what must change is the structure of the molecule but the same condensed formula must be maintained. With this in mind we can have the following options for each of the molecules given by the problem:
(a) [tex]C_3H_7Cl[/tex]
-) 1-Chloropropane
-) 2-Chloropropane
(b) [tex]C_4H_1_0[/tex]
-) butane
-) isobutane
(c) [tex]C_5H_1_2[/tex]
-) n-pentane
-) isopentane
-) neopentane
(d) [tex]C_4H_1_0O[/tex]
-) butan 1-ol
-) butan 2-ol
-) 2-methylpropan-1-ol
-) 2-methylpropan-2-ol
-) 1-methoxypropane
-) ethoxyethane
-) 2-methoxypropane
(e) [tex]C_3H_6Cl_2[/tex]
-) 1,1-dichloropropane
-) 1,2-dichloropropane
-) 1,3-dichloropropane
-) 2,2-dichloropropane
See figure 1 to further explanations
I hope it helps!
