Complete the description of the piecewise function graphed below. Use interval notation to indicate intervals.

Answer:
{ -2 if x ∈ -4 < x < -3
{ -5 if x ∈ -3 ≤ x < 2
[ 5 if x ∈ 2 ≤ x < 5
Step-by-step explanation:
From the graph, we have;
{ -2 if x ∈ -4 < x < -3
For the next inequality line at y = -5, we have;
1) The inequality line, starts with an open circle on the left at x = -3, which is equivalent to less than or equal to symbol, ≤ as -3 ≤ x because the point x =-3 is the left boundary. The inequality line extends to the point x = 2, where we have a closed circle (on the right), which is equivalent to a x ≤ 2 with the 2 on the right hand side because, the 2 is the right boundary of the inequality
2) The inequality can be summarized as starting from x = -3 extends to x = 2
3) As stated in point 1) the point x = 3, we have -3 ≤ x and at point x = 2, we have x ≤ 3 which can be combined as -3 ≤ x < 2, to give;
{ -5 if x ∈ -3 ≤ x < 2
For the next inequality line at y = 5, we have;
1) The inequality line, starts with an open circle on the left at x = 2, which is equivalent to less than or equal to symbol, ≤ as 2 ≤ x because the point x =2 is the left boundary. The inequality line extends to the right to reach point x = 5, where we have a closed circle (on the right), which is equivalent to a x ≤ 5 inequality, with the 5 on the right hand side because, the 5 is the right boundary of the inequality
2) The inequality can be summarized as starting from x = 2 extends to x = 5
3) As stated in point 1) the point x = 2, we have 2 ≤ x and at point x = 5, we have x ≤ 5 which can be combined as 2 ≤ x < 5, to give;
[ 5 if x ∈ 2 ≤ x < 5.
Answer:
1st box = [-4, -3]
2nd box = (-3, 2]
3rd box = (2, 5]
For f(x) = -2 we see that x is between -4 to -3 with closed endpoints.
So the interval will be [-4, -3].
For f(x) = -5 we see that x is between -3 to 2 with closed endpoint at 2 and open endpoints at -3.
So the interval will be (-3, 2].
For f(x) = 5 we see that x is between 2 to 5 with open endpoint at 2 and closed endpoint at 5.
So the interval will be (2, 5].
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