the angle he jumped from the ground is 8.92°
The question above is a projectile motion problem, and we can solve it using the formula of range.
⇒ Formula:
- R = u²sin2∅/g................... Equation 1
⇒ Where:
- R = Range of the runner
- u = initial velocity
- g = acceleration due to gravity
- ∅ = angle to the horizontal
From the question,
⇒ Given:
- R = 8 m
- u = 16 m/s
- g = constant = 9.8 m/s²
⇒Substitute these values into equation 1
⇒ Solve for ∅
- 8×9.8 = 16²sin2∅
- 78.4 = 256sin2∅
- sin2∅ = 78.4/256
- sin2∅ = 0.30625
- 2∅ = sin⁻¹(0.30625)
- 2∅ = 17.83
- ∅ = 17.83/2
- ∅ = 8.92°
Hence the angle he jumped from the ground is 8.92°
Learn more about range here: https://brainly.com/question/15502195
