Question

please help me
sec theta - cos theta= sin^2 theta/ cos theta​

Answer 1

Answer:

Taking LHS

=1 by cos theta- cos theta

= (1- cos²0)/ cos0

= sin²0/ cos0 ( because 1-cos²0 is also equals to sin²0)

=RHS hence proved

Answer 2

Answer:

Step-by-step explanation:

Let theta be β.

So,

$sec\beta - cos\beta = \frac{sin^2\beta }{cos\beta } \\=>\frac{1}{cos\beta } - cos\beta = \frac{1 - cos^2\beta }{cos\beta } \\=>\frac{1 - cos^2}{cos\beta } = \frac{1 - cos^2\beta }{cos\beta }$

Here , identity used = $sin^2\beta + cos^2\beta = 1$