Question

7n²mp⁴ • 3n³m⁴p-⁴ (that's supposed to be a negative exponent)​

Answer 1

Answer:

When we are multiplying eponents with the same base, we do is writing the sum of both exponents:

$a^n*a^m = a^{n+m}$

SO, in our case:

$7n^2mp^4*3n^3m^4p^{-4}$

We have to do this three times and multiply the numbers:

$7n^2mp^4*3n^3m^4p^{-4} = 7*3*n^{2+3}*m^{1+4}*p^{4+(-4)}$ = $21n^5m^5p^0$ (any number whose exponent is equal to 0 has a value of 1) = $21n^5p^5$

So now we know that $7n^2mp^4*3n^3m^4p^{-4}=21n^5m^5$ =