Question

A billiard ball moves with 3 kg⋅m/s of momentum and strikes three other billiard balls. What is the total momentum of the balls after the collision?
(1 point)
more than 3 kg⋅m/s
3 kg⋅m/s
It depends on the mass of each ball.
less than 3 kg⋅m/s

Answer 1

A billiard ball moves with 3 kg⋅m/s of momentum and strikes three other billiard balls that have been just sitting there at rest and not moving.

The total momentum of all four balls after the collision is 3 kg⋅m/s, because momentum is not created or destroyed.  The total amount of it after an event is the same as the total amount of it before the event.

Answer 2

The momentum of the billiard balls after the collision is 3 Kgm/s.

• Let the billiard ball be B.

Given the following data:

• Momentum B = 3 Kgm/s

To find the momentum of the balls after the collision:

Momentum is simply a multiplication (product) of the mass of an object with its velocity.  Also, momentum is a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

$Momentum = Mass$ × $Velocity$

$Total \; momentum = Momentum \; B + Momentum \;of \;the \;other\; balls.$

Since the other billiard balls were at rest (not experience any motion), there velocities would be zero (0) m/s.

Substituting the given values, we have:

$Total \; Momentum = 3 + 0$

Total momentum = 3 Kgm/s.

Therefore, the momentum of the billiard balls after the collision is 3 Kgm/s.

Find more information: https://brainly.com/question/3556616