Question

Find the equation of a line containing the point (8.3) and has a slope of 5. Write
the equation in slope-intercept form

Answer 1

Answer:

$y=5x-37$

Step-by-step explanation:

So we want to find the equation of a line with a slope of 5 and passes through (8,3).

To do so, we can use the point-slope form. This point-slope form is:

$y-y_1=m(x-x_1)$

Let's let (8,3) be x₁ and y₁ and let's let m equal 5. Therefore:

$y-3=5(x-8)$

Distribute the right:

$y-3=5x-40$

Add 3 to both sides:

$y=5x-37$

That would be our equation in slope-intercept form.

And we're done!

Answer 2

Y=5x-37 and your all done