Question

An experienced carpenter can frame a house twice as fast as an apprentice. Working together, it takes the carpenters 2 days. How long would it take the apprentice working alone?

Answer 1

Answer:

6 days

Step-by-step explanation:

Let the time taken by Carpenter working alone = $C$ days

Then time taken by apprentice alone = Twice as that of taken by Carpenter = 2$C$ days

Time taken working together = 2 days

Work done in one day working together = $\frac{1}{2}$

Work done in one day by Carpenter working alone = $\frac{1}{C}$

Work done in one day by apprentice working alone = $\frac{1}{2C}$

Work done in one day by Carpenter working alone + Work done in one day by Carpenter working alone =  $\frac{1}{C}$+$\frac{1}{2C}$ = Work done in one day working together = $\frac{1}{2}$

$\dfrac{1}{C}+\dfrac{1}{2C}=\dfrac{1}{2}\\\Rightarrow \dfrac{2+1}{2C}=\dfrac{1}{2}\\\Rightarrow C = 3\ days$

Time taken by Carpenter alone to complete the work = 3 days

Time taken by Apprentice alone to complete the work = 3 $\times$ 2= 6 days

Answer 2

We are required to calculate the number of days it would take the apprentice working alone

The number of days it takes the apprentice working alone is 6 days

let

Number of days taken for the carpenter to work alone = x

Number of days taken by the apprentice to work alone = 2x

Number of days taken to work together = 2 days

Work done per day Carpenter = 1/x

work done per day apprentice = 1/2x

work done per day together = 1/2

So,

work done per day together = Work done per day Carpenter + work done per day apprentice

1/2 = 1/x + 1/2x

1/2 = (2 + 1) / 2x

1/2 = 3/2x

cross product

1(2x) = 2(3)

2x = 6

x = 6/2

x = 3 days

Therefore,

Number of days taken by the apprentice to work alone = 2x

= 2(3)

= 6 days

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