.If m∠ ROT = 155, what are m ∠ ROS and m∠TOS?
Can someone explain how to do it also?

Answer:
ROS=72° TOS=83°
Step-by-step explanation:
(4x-20)+(3x+14)=155
7x-6=155
7x=161
x=23
4(23)-20=72
3(23)+14=83
Answer:
ROS is 72 degrees.
TOS is 83 degrees.
Step-by-step explanation:
So we know that the measure of Angle ROT is 155.
Angle ROT is the combined value of Angle ROS and Angle TOS. In other words:
[tex]ROT=ROS+TOS[/tex]
Substitute 155 for ROT, (4x-20) for ROS, and (3x+14) for TOS. Thus:
[tex]155=(4x-20)+(3x+14)[/tex]
Combine like terms:
[tex]155=(4x+3x)+(-20+14)[/tex]
Add:
[tex]155=7x-6[/tex]
Add 6 to both sides:
[tex]161=7x[/tex]
Divide both sides by 7:
[tex]x=23[/tex]
So, the value of x is 23.
Now, plug that into each of the Angle equations to solve for each angle:
[tex]ROS=4x-20\\ROS=4(23)-20[/tex]
Multiply:
[tex]ROS=92-20[/tex]
Subtract:
[tex]ROS=72[/tex]
Same thing for TOS:
[tex]TOS=3x+14\\TOS=3(23)+14[/tex]
Multiply:
[tex]TOS=69+14[/tex]
Add:
[tex]TOS=83[/tex]
And we're done!