Question

A random sample of adults were asked whether they prefer reading an e-book over a printed book. The survey resulted in a sample proportion of p′=0.14, with a sampling standard deviation of σp′=0.02, who preferred reading an e-book.

Answer 1

Answer:

The confidence interval is  (0.1008, 0.1792)

Step-by-step explanation:

According to the question, the data provided is as follows

p′=0.14

sampling standard deviation of σp′= 0.02

Based on the above information

The computation of the 95% confidence interval for the true or correct proportion is

Here we apply the z value of 95% confidence interval i.e. 1.96

Now the confidence interval is

$= (pcap - z\times sigma, pcap + z\times sigma)\\\\= (0.14 - 1.96\times 0.02, 0.14 + 1.96\times 0.02)\\\\= (0.1008, 0.1792)$