Question

Between which two integers does square root of /51 lie

Answer 1

Answer:

7 and 8

Step-by-step explanation:

Consider the perfect squares either side of 51

49 < 51 < 64 , thus

$\sqrt{49}$ < $\sqrt{51}$ < $\sqrt{64}$ , that is

7 < $\sqrt{51}$ < 8

Answer 2

Answer:

7 and 8.

Step-by-step explanation:

7^2 = 49 and 8^2 = 64.