Answer:
a = [tex]\frac{9}{2}[/tex]
Step-by-step explanation:
To find the value of a, find the Slope of both the equations.
For lines to be perpendicular to each other [tex]m_{1}m_{2} = - 1[/tex]
For line 1:
2x + 3y − 6 = 0 represent the line in y=mx +c form
3y = -2x + 6
y = [tex]\frac{-2}{3} x[/tex] + [tex]\frac{6}{3}[/tex]
y = [tex]\frac{-2}{3} x[/tex] + 2
[tex]m_{1}[/tex] = [tex]\frac{-2}{3}[/tex]
For line 2:
ax - 3y = 5
ax = 5 + 3y
ax - 5 = 3y
y = [tex]\frac{ax}{3} - \frac{5}{3}[/tex]
[tex]m_{2}[/tex] = [tex]\frac{a}{3}[/tex]
Apply the condition of perpendicularity:
[tex]\frac{-2}{3}[/tex] * [tex]\frac{a}{3}[/tex] = - 1
[tex]\frac{2a}{9} = 1[/tex]
a = [tex]\frac{9}{2}[/tex]
