Respuesta :
Answer:
[tex]f^{-1}(x)=\sqrt[5]{\frac{x+11}{6}}[/tex]
Step-by-step explanation:
So we have the function:
[tex]f(x)=6x^5-11[/tex]
To find the inverse of a function, switch f(x) and x, change f(x) to f⁻¹(x), and solve for f⁻¹(x). So:
[tex]f(x)=6x^5-11\\x=6(f^{-1}(x))^5-11[/tex]
Add 11 to both sides:
[tex]x+11=6(f^{-1}(x))^5[/tex]
Divide both sides by 6:
[tex]\frac{x+11}{6}=f^{-1}(x)^5[/tex]
Take the fifth root of each side:
[tex]f^{-1}(x)=\sqrt[5]{\frac{x+11}{6}}[/tex]
And we're done :)
Answer:
[tex]f^-^1(x)=\sqrt[5]{\frac{x+11}{6} }[/tex]
Step-by-step explanation:
[tex]f(x)=6x^5-11\\[/tex]
Let y equal the equation
[tex]y =6x^5-11\\y+11=6x^5\\\\Divide\:both\:sides\:of\:the\:equation\:by \: 6\\\frac{y+11}{6} = \frac{6x^5}{6} \\\\\frac{y+11}{6} = x^5\\ \\Quatric\:root\:both\:sides\\\sqrt[5]{\frac{y+11}{6} } = \sqrt[5]{x^5} \\\\\sqrt[5]{\frac{y+11}{6} } = x\\\\f^-^1(x) = \sqrt[5]{\frac{x+11}{6} }[/tex]