PLEASE HELP!!! TRIG, Theres a picture!!

Answer:
Step-by-step explanation:
[tex]3( { \tan }^{2} \theta - { \sec }^{2} \theta)[/tex]
Using trigonometric identities
That's
[tex]1 + { \tan }^{2} \theta = { \sec }^{2} \theta[/tex]
Rewrite the expression
That's
[tex]3({ \tan }^{2} \theta - (1 + { \tan }^{2} \theta)) \\ [/tex]
Simplify
We have
[tex]3({ \tan }^{2} \theta - 1 - { \tan }^{2} \theta) \\ 3({ \tan }^{2} \theta - { \tan }^{2} \theta - 1)[/tex]
So we have
3( - 1)
We have the final answer as
Hope this helps you