Question

3(2x-1)=4x+12 what value of X satisfies the equation above

Answer 1

Answer:

$x = \frac{15}{2} \\\\x =7\frac{1}{2}$

Step-by-step explanation:

$3\left(2x-1\right)=4x+12\\\\\mathrm{Expand\:}3\left(2x-1\right):\quad 6x-3\\6x-3=4x+12\\\\\mathrm{Add\:}3\mathrm{\:to\:both\:sides}\\6x-3+3=4x+12+3\\\\Simplify\\6x=4x+15\\\\\mathrm{Subtract\:}4x\mathrm{\:from\:both\:sides}\\6x-4x=4x+15-4x\\\\Simplify\\2x =15\\\\\mathrm{Divide\:both\:sides\:by\:}2\\\frac{2x}{2}=\frac{15}{2}\\\\Simplify\\x = 15/2$

Answer 2

Answer:

$7\frac{1}{2}$

Step-by-step explanation:

$3(2x-1)=4x+12$

Use 3 to open the bracket

$3(2x-1) = 6x -3\\\\ 6x-3 = 4x+12$

Collect like terms and simplify

$6x-4x = 12+3\\2x = 15$

Divide both sides of the equation by 2

$\frac{2x}{2} = \frac{15}{2} \\\\x = \frac{15}{2} = 7\frac{1}{2}$