Question

16. Write the equation of line that contains
the points (1, 2) and (3, 0).

Answer 1

Answer:

y=-1x+3

I honestly have no idea how I would explain this. Apologies.

Answer 2

Answer:

[see below]

Step-by-step explanation:

Finding Slope:

m = $\frac{rise}{run}=\frac{0-2}{3-1}=\frac{-2}{2}=-1$

Using the slope and a point to make a point slope equation:

$y-y_1=m(x-x_1)$

m = -1  (x,y) = (1,2)

Plug values:

$y-2=-1(x-1)$

Convert the equation into slope-intercept:

$y-2=-1(x-1)\\\\y-2=-1x+1\\\\y-2+2=-1x+1+2\\\\y=-1x+3\\\\\boxed{y=-x+3}$

Hope this helps.