The height of a triangle is 4 inches. Greater than twice it's base. The area of the triangle is no more than 168 in.². Which any quality can be used to find the possible lengths, x, of the base of the triangle

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Step-by-step explanation:

this problem seeks to test our knowledge on word problems and algebra

Solution

let the base be x, and

the height h = 2x+4

We know that area of a triangle is given as

[tex]A= \frac{1}{2} b*h[/tex]

substituting our given values we have

[tex]168= \frac{1}{2} x*(2x+4)\\\\168= \frac{2x^2+4x}{2} \\\\168= x^2+2x\\\\[/tex]

re-arranging we have

[tex]x^2+2x-168=0\\\\[/tex]

we can now find two factors that will add up to give 2 and multiply to give -168

they are 14 and -12

[tex]x^2-14x+12x-168=0\\\\x(x-14)+12(x- 14)=0\\\\x+12=0\\\\x=-12\\\\x-14=0\\\\x=14[/tex]

The possible base of the triangle is 14 in

and the height is

[tex]h= 2x+4\\\\h=2(14)+4\\\\h= 28+4\\\\\h= 32 in[/tex]

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