Step-by-step explanation:
this problem seeks to test our knowledge on word problems and algebra
Solution
let the base be x, and
the height h = 2x+4
We know that area of a triangle is given as
[tex]A= \frac{1}{2} b*h[/tex]
substituting our given values we have
[tex]168= \frac{1}{2} x*(2x+4)\\\\168= \frac{2x^2+4x}{2} \\\\168= x^2+2x\\\\[/tex]
re-arranging we have
[tex]x^2+2x-168=0\\\\[/tex]
we can now find two factors that will add up to give 2 and multiply to give -168
they are 14 and -12
[tex]x^2-14x+12x-168=0\\\\x(x-14)+12(x- 14)=0\\\\x+12=0\\\\x=-12\\\\x-14=0\\\\x=14[/tex]
The possible base of the triangle is 14 in
and the height is
[tex]h= 2x+4\\\\h=2(14)+4\\\\h= 28+4\\\\\h= 32 in[/tex]