Question

how many gallons of a 80% antifreeze solution must be mixed with 70 gallons of 30% antifreeze to get a mixture that is 70% antifreeze

Answer 1

let x=gallons of 80% solution to be mixed
x+80=gallons go final 70% mixture
..
80%*x+30%*80=70%*(x+80)
.8x+24=.7x+56
.1x=32
x=320
gallons of 80% solution to be mixed=320