Question

the point-slope form of the equation that passes through (-4, -3) and (12, 1) is y - 1 = 1/4(x-12). what is the standard form of the equation for this line?
A) x-4y=8
B) x-4y=2
C) 4x-y=8
D) 4x-y=2

Answer 1

Answer:

A

Step-by-step explanation:

So we know that the point-slope form of the line that passes through the points (-4,-3) and (12,1) is:

$y-1=\frac{1}{4}(x-12)$

And we want to convert this to standard form.

The standard form of a linear equation is:

$Ax+By=C$

Where A, B, and C are integers, and, traditionally, A is positive.

So, first, multiply everything by 4 to remove the negative:

$4(y-1)=4(\frac{1}{4}(x-12))$

Distribute the left. The right cancels:

$4y-4=x-12$

Add 4 to both sides. The left cancels:

$4y=x-8$

Subtract x from both sides:

$-x+4y=-8$

As I mentioned previously, the coefficient of A tends to be positive. So, divide everything by -1:

$(-x+4y)/-1=(-8)/-1$

Simplify:

$x-4y=8$

So, our answer is A

And we're done!