Answer:
x = 95°
Step-by-step explanation:
[tex] m\angle Q = 360\degree - 235\degree = 125\degree \\[/tex]
Produce QR In such a way that it intersects ray ST at any point say M.
PQ || ST... (given) and Seg QM is transversal.
[tex] \therefore m\angle PQM + m\angle SMQ = 180\degree \\(interior \: \angle \:Postulate) \\
\therefore 125\degree + m\angle SMQ = 180\degree \\
\therefore m\angle SMQ = 180\degree -125\degree \\
\therefore m\angle SMQ = 55\degree \\
In\: \triangle SMR, \: x \: is \:exterior \: \angle \\
\therefore x = 40\degree + 55\degree \\
\huge \purple {\boxed {\therefore x = 95\degree}} [/tex]
