Question

3(y+3)+7(2y-8)-(y-1)=0​

Answer 1

Answer:

We have this equation:

$3(y+3)+7(2y-8)-(y-1)=0​$

First, we do the parenthesis:

$3y+9+14y-56-(y-1)=0$

When there is a minus (-) in front of a parenthesis, all signs change inside it:

$3y+9+14y-56-y+1)=0$

Now we operate:

$16y-46=0$

We add 46 on both sides:

$16y - 46 + 46 = 0 +46$

$16y = 46$

And divide 16 on both sides:

$\frac{16y}{16}=\frac{46}{16}$

$\bol{x = \frac{46}{16}}$ = $\frac{23}{8}$

Answer 2

Answer:

Step-by-step explanation:

3(y+3)+7(2y-8)-(y-1)=0​

3y + 9 + 14y - 56 - y + 1 = 0

16y - 46 = 0

16y - 46 + 46 = 0 + 46

16y = 46

16y/16 = 46/16

y = 23/8