contestada

Find the equation of the line perpendicular to y=2x-6 that passes through the point (1,5). If possible, write the equation in slope-intercept form.

Respuesta :

Answer:

[tex]y=-0.5x+4.5[/tex]

Step-by-step explanation:

The slope of [tex]y=2x-6[/tex] is:

  • [tex]2[/tex]

The negative reciprocal of that slope is:

  • [tex]m=-\frac{1}{2}[/tex]

So the perpendicular line will have a slope of [tex]-1/2[/tex]:

  • [tex]y - y_1 = (-\frac{1}{2} )(x - x_1)[/tex]

And now put in the point [tex](1,5)[/tex]:

  • [tex]y-5=(-\frac{1}{2})(x-1)[/tex]

And that answer is OK, but let's also put it in [tex]y=mx+b[/tex] form:

  • [tex]y-5=-\frac{x}{2}+\frac{1}{2}[/tex]
  • [tex]y=-\frac{x}{2}+\frac{11}{2}[/tex]
  • [tex]y=-0.5x+4.5[/tex]
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