Question

solve the equation (2^2x +2) (2^3x -7)= 2^25

Answer 1

Answer:

$\Huge \boxed{x=6}$

$\rule[225]{225}{2}$

Step-by-step explanation:

$(2^{2x +2}) (2^{3x -7})= 2^{25}$

When multiplying same bases, add the exponents.

$(2^{2x +2+3x -7})= 2^{25}$

$(2^{5x -5})= 2^{25}$

Cancelling the same bases from both sides.

$5x-5=25$

Adding 5 to both sides.

$5x=30$

Dividing both sides by 5.

$x=6$

$\rule[225]{225}{2}$