Answer:
The confidence interval is [tex]13.4< \mu < 13.8[/tex]
Step-by-step explanation:
From the question we are told that
The sample mean is [tex]\= x = 13.6[/tex]
The standard deviation is [tex]\sigma = 1.9[/tex]
The sample size is [tex]n = 189[/tex]
given that the confidence level is 85% then the level of significance is mathematically represented as
[tex]\alpha = (100 - 85 )\%[/tex]
[tex]\alpha = 0.15[/tex]
Next we obtain the critical value of [tex]\frac{\alpha }{2}[/tex] from the normal distribution table the value is
[tex]Z_{\frac{\alpha }{2} } = 1.44[/tex]
Generally the margin of error is mathematically represented as
[tex]E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }[/tex]
=> [tex]E = 1.44* \frac{1.9}{\sqrt{189} }[/tex]
=> [tex]E = 0.1990[/tex]
The 85% confidence interval is mathematically represented as
[tex]\= x - E < \mu <\= x + E[/tex]
=> [tex]13.6- 0.1990 < \mu < 13.6+ 0.1990[/tex]
=> [tex]13.4< \mu < 13.8[/tex]