Answer:
[tex]m_{solute}=3.62g\\\\m_{solvent}=57.38g[/tex]
Explanation:
Hello,
In this case, since the given concentration is molality, we have:
[tex]m=\frac{mol_{solute}}{mass_{solvent}}[/tex]
Whereas the mass of the solvent (water for aqueous solution) is given in kg. Moreover, since the total mass of the solution is 61.0 g, one could write:
[tex]m_{solute}+m_{solvent}=61.0h\\\\m_{solvent}=61.0g-m_{solute}[/tex]
Which is replaced in the definition of molality:
[tex]m=\frac{mass_{solute}*\frac{1mol}{119g} }{(61.0g-m_{solute})*\frac{1kg}{1000g} }\\\\0.530m=\frac{8.4mass_{solute}}{61.0-mass_{solute}}[/tex]
Thus, solving for the mass of solution we obtain:
[tex]mass_{solute}=3.62g[/tex]
Therefore, the mass of the solvent is:
[tex]m_{solvent}=61.0g-3.62g\\\\m_{solvent}=57.38g[/tex]
Best regards.
