Please help me to prove this..

Step-by-step explanation:
1 / (sin 10°) − √3 / (cos 10°)
Multiply top and bottom of the first fraction by ½ cos 10°.
½ cos 10° / (½ cos 10° sin 10°) − √3 / (cos 10°)
Multiply top and bottom of the second fraction by ½ sin 10°.
½ cos 10° / (½ cos 10° sin 10°) − ½√3 sin 10° / (½ sin 10° cos 10°)
Combine fractions.
(½ cos 10° − ½√3 sin 10°) / (½ sin 10° cos 10°)
Change ½ to sin 30°, and change ½√3 to cos 30°.
(sin 30° cos 10° − cos 30° sin 10°) / (½ sin 10° cos 10°)
Use angle sum formula.
sin(30° − 10°) / (½ sin 10° cos 10°)
sin 20° / (½ sin 10° cos 10°)
Multiply top and bottom by 4.
4 sin 20° / (2 sin 10° cos 10°)
Use double angle formula.
4 sin 20° / sin 20°
4
We are given the equation 1 / sin(10°) - √3 / cos(10°) = 4, and want to prove that 1 / sin(10°) - √3 / cos(10°) equals 4.
Let's start by combining the expressions '1 / sin(10°)' and '√3 / cos(10°)' in the expression '1 / sin(10°) - √3 / cos(10°).'
1 / sin(10°) - √3 / cos(10°)
= cos(10°) - √3sin(10°) / sin(10°) [tex]*[/tex] cos(10°)
Now let's multiply the numerator and denominator by a common value. In this case it's most suitable to multiply both by 2. We will receive the expression 2(cos(10°) - √3sin(10°)) / 2(sin(10°) [tex]*[/tex] cos(10°)). We can further simplify this expression knowing that 2(sin(10°) [tex]*[/tex] cos(10°)) = 2sin(20°).
2(cos(10°) - √3sin(10°)) / 2sin(20°)
We can now bring the two on the bottom to the numerator, becoming 1 / 2. Remember that the ' 1 / 2 ' will be distributed now. After the distribution we receive the expression 4( 1 / 2(cos(10°) - √3 / 2sin(10°)) / 2sin(20°). We can now use the trivial functions 1 / 2 = sin(30°), and √3 / 2 = cos(30°).
4(sin(30°)(cos(10°) - cos(30°)(sin(10°) ) / sin(20°))
= 4((sin(30 - 10°)) / sin(20°) = 4