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Complete Question  

Find the average value of the function over the given interval. (Round your answer to three decimal places.) f(x) = 12e^x, [−6, 6] Find all values of x in the interval for which the function equals its average value. (Enter your answers as a comma-separated list. Round your answers to three decimal places.)

Answer:

The  average is  

  [tex]AV  =  403[/tex]

The value of  x is

   [tex]x =  4[/tex]

Step-by-step explanation:

From the question we are told that

  The equation is  [tex]f(t) =  12e^x[/tex]

  The  points consider is  [-6 , 6]

Generally the average value of the function over the given interval is mathematically represented as

          [tex]AV  =  \frac{1}{z-w} \int\limits^ z_w {f(x)} \, dx[/tex]

          [tex]AV  =  \frac{1}{ 6 - (-6)}  \int\limits^{6}_{-6} { 12e^x} \, dx[/tex]

          [tex]AV  =  \frac{1}{12 } e^x| \left 6} \atop {-6}} \right.[/tex]

          [tex]AV  = e^6 -e^{-6}[/tex]

          [tex]AV  =  403[/tex]

Generally when the function equal the average we have that

        [tex]f(x) =  12e^{x} =  403[/tex]

        [tex]e^{x} =  34[/tex]

          [tex]x =  ln(34)[/tex]

        [tex]x =  4[/tex]

         

       

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