Complete Question
Find the average value of the function over the given interval. (Round your answer to three decimal places.) f(x) = 12e^x, [−6, 6] Find all values of x in the interval for which the function equals its average value. (Enter your answers as a comma-separated list. Round your answers to three decimal places.)
Answer:
The average is
[tex]AV = 403[/tex]
The value of x is
[tex]x = 4[/tex]
Step-by-step explanation:
From the question we are told that
The equation is [tex]f(t) = 12e^x[/tex]
The points consider is [-6 , 6]
Generally the average value of the function over the given interval is mathematically represented as
[tex]AV = \frac{1}{z-w} \int\limits^ z_w {f(x)} \, dx[/tex]
[tex]AV = \frac{1}{ 6 - (-6)} \int\limits^{6}_{-6} { 12e^x} \, dx[/tex]
[tex]AV = \frac{1}{12 } e^x| \left 6} \atop {-6}} \right.[/tex]
[tex]AV = e^6 -e^{-6}[/tex]
[tex]AV = 403[/tex]
Generally when the function equal the average we have that
[tex]f(x) = 12e^{x} = 403[/tex]
[tex]e^{x} = 34[/tex]
[tex]x = ln(34)[/tex]
[tex]x = 4[/tex]