Respuesta :

Answer:

The  value is   [tex]Q_{net} =  1.239 *10^{-6} \  C[/tex]

Explanation:

From the question we are told that

   The electric flux is [tex]\Phi =  1.4*10^{5} \  N\cdot m^2/C[/tex]

     

Generally the net charge is mathematically represented as

    [tex]Q_{net} =  \Phi *  \epsilon_o[/tex]

Here [tex]\epsilon_o[/tex] is the permetivity of free space with value  

       [tex]\epsilon_o =  8.85*10^{-12}  \  \  m^{-3} \cdot kg^{-1}\cdot  s^4 \cdot A^2[/tex]

So

   [tex]Q_{net} =  1.4*10^5 *  8.85*10^{-12}[/tex]

=>   [tex]Q_{net} =  1.239 *10^{-6} \  C[/tex]

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