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Complete Question

A circular area with a radius of 6.60 cm lies in the xy-plane. What is the magnitude of the magnetic flux through this circle due to a uniform magnetic field B = 0.250 T oriented in the following ways?

(a) in the +z-direction

Wb

(b) at an angle of 54

Answer:

a

[tex]\phi = 0.00342 \ Wb[/tex]

b

[tex]\phi = 0.00201 \ Wb[/tex]

Explanation:

From the question we are told that

   The  radius is  [tex]r = 6.60 \ cm = 0.066 \ m[/tex]

    The magnitude of the magnetic field is [tex]B = 0.250 \ T[/tex]

Generally the cross -sectional area is mathematically represented as

     [tex]A = \pi r^2[/tex]

     [tex]A = 3.142 * (0.066)^2[/tex]

     [tex]A = 0.01369 \ m^2[/tex]

Generally  when the magnetic field is oriented in the +z-direction the magnetic flux is mathematically represented as

      [tex]\phi = B* A cos(0)[/tex]

=>    [tex]\phi = 0.01369 * 0.250 * cos (0)[/tex]

=>     [tex]\phi = 0.00342 \ Wb[/tex]

  Now when the magnetic field is oriented  at an angle of 54°  the magnetic flux is mathematically represented as

      [tex]\phi = B* A cos(54)[/tex]

      [tex]\phi = 0.01369 * 0.250 * cos (54)[/tex]

     [tex]\phi = 0.00201 \ Wb[/tex]

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