Complete Question
A circular area with a radius of 6.60 cm lies in the xy-plane. What is the magnitude of the magnetic flux through this circle due to a uniform magnetic field B = 0.250 T oriented in the following ways?
(a) in the +z-direction
Wb
(b) at an angle of 54
Answer:
a
[tex]\phi = 0.00342 \ Wb[/tex]
b
[tex]\phi = 0.00201 \ Wb[/tex]
Explanation:
From the question we are told that
The radius is [tex]r = 6.60 \ cm = 0.066 \ m[/tex]
The magnitude of the magnetic field is [tex]B = 0.250 \ T[/tex]
Generally the cross -sectional area is mathematically represented as
[tex]A = \pi r^2[/tex]
[tex]A = 3.142 * (0.066)^2[/tex]
[tex]A = 0.01369 \ m^2[/tex]
Generally when the magnetic field is oriented in the +z-direction the magnetic flux is mathematically represented as
[tex]\phi = B* A cos(0)[/tex]
=> [tex]\phi = 0.01369 * 0.250 * cos (0)[/tex]
=> [tex]\phi = 0.00342 \ Wb[/tex]
Now when the magnetic field is oriented at an angle of 54° the magnetic flux is mathematically represented as
[tex]\phi = B* A cos(54)[/tex]
[tex]\phi = 0.01369 * 0.250 * cos (54)[/tex]
[tex]\phi = 0.00201 \ Wb[/tex]