Question

Find ​(a) PQ to the nearest tenth and ​(b) the coordinates of the midpoint of PQ. ​P(​-6,​6), ​Q(​4,-1​)

Answer 1

Answer:

a)   PQ = 12.2

b)   M (-1, 2.5)

Step-by-step explanation:

a) PQ

use pythagorean PQ = $\sqrt{(6+4)^2 +(6+1)^2}$

PQ = $\sqrt{149}$ = 12.2

b) Midpoint

Mx = (-6 + 4)/2 = -1

My = (6 + -1)/2 = 2.5

Answer 2

Answer:

$\Huge \boxed{\mathrm{a) \ 12.21}} \\\\\\\\ \huge \boxed{\mathrm{b) \ -1, \ \frac{5}{2}}}$

$\rule[225]{225}{2}$

Step-by-step explanation:

(a)

We can use Pythagorean theorem to solve for the length of PQ.

$PQ=\sqrt{10^2 +7^2 }$

$PQ=\sqrt{149} \approx 12.2066$

The length of PQ is approximately 12.21.

(b)

We can find the midpoint with the midpoint formula:

$\displaystyle \frac{x_1 + x_2 }{2}, \ \frac{y_1+y_2}{2}$

$\displaystyle \frac{-6+4 }{2}, \ \frac{6+-1}{2}$

$\displaystyle \frac{-2 }{2}, \ \frac{5}{2}$

$\displaystyle -1, \ \frac{5}{2}$

$\rule[225]{225}{2}$