Question

How large a net force is required to accelerate a 1600-kg SUV from rest to a speed of 25 m/s in a distance of 200 m

Answer 1

Answer:

F=2496 N

Explanation:

Given that,

Mass of SUV, m = 1600 kg

Initial speed, u = 0

Final speed, v = 25 m/s

Distance, d = 200 m

We need to find the net force. Firstly, let's find acceleration using equation of motion.

$v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(25)^2-(0)^2}{2\times 200}\\\\a=1.56\ m/s^2$

Net force, F = ma

$F=1600\times 1.56\\\\F=2496\ N$

So, the net force is 2496 N.

Answer 2

The amount of net force that will be required to accelerate a 1600kg SUV from rest to a speed of 25 m/s in a distance of 200m is 2500N

HOW TO CALCULATE NET FORCE:

• The net force of a body can be calculated by multiplying its mass by acceleration.

• However, the acceleration of this SUV needs to be calculated using the following equation of motion:

• v² - u² = 2as

• a = v² - u²/2s

Where:

1. a = acceleration (m/s²)
2. v = final velocity (m/s)
3. u = initial velocity (m/s)
4. s = distance (m)

• a = 25² - 0²/2(200)

• a = 625/400

• a = 1.563m/s²

Since a = 1.563m/s²

• F = 1600 × 1.563

• F = 2500N

• Therefore, the amount of net force that will be required to accelerate a 1600kg SUV from rest to a speed of 25 m/s in a distance of 200m is 2500N.

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