A baseball player hits a pop fly ball toward left field where it is caught by a player at a height of 5 feet. The ball was hit at a height of 3 feet and reached a height of 50 feet. The height of the ball is a function of time. What is the range of this function?

Respuesta :

Answer:

The range of the function are the values of height which are from 3, 4, 5, ..., 50

Step-by-step explanation:

The given parameters are;

The height at which the ball is caught = 5 feet

The height at which the ball was hit = 3 feet

The maximum height reached by the ball = 50 feet

The height of the ball given as a function of time is f(t) s = u·t - 1/2·g·t²

Where;

s = 50 feet

g = 9.81 m/s²

Therefore, we have;

50 = u·t - 1/2 × 9.81 × t²

50 = u·t - 4.905 × t²

Therefore, the range are obtainable values for f(t) which range from 3 to 50.

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