Question

What is the mass of an rock that has a density of 3.52 g/cc. and when put in a graduated cylinder with 50ml of water makes the level rise to 62ml.

Answer 1

Answer:

m = 42.24 grams

Explanation:

Given that,

The density of the mass of a rock is 3.52 g/cm³.

Initial volume of the graduated cylinder is 50 mL and when rock is put in it the water level makes the level rise to 62 mL.

We need to find the mass of the rock.

Volume of rock = final volume - initial volume

Volume of rock = 62 mL - 50 mL

Volume of rock = 12 mL

1 ml = 1 cm³

So, 12 mL = 12 cm³

Density=mass/volume

$m=d\times V\\\\m=3.52\ g/cm^3\times 12\ cm^3\\\\m=42.24\ g$

So, the mass of the rock is 42.24 grams.

Answer 2

The mass of the rock is 42.24 g

We'll begin by calculating the the volume of the rock.

• Volume of water = 50 mL

• Volume of water + rock = 62 mL

• Volume of rock =?

Volume of rock = (Volume of water + rock) – (Volume of water)

Volume of rock = 62 – 50

Volume of rock = 12 mL

Finally, we shall determine the mass of the rock.

• Volume of rock = 12 mL

• Density of rock = 3.52 g/cm³ = 3.52 g/mL

Mass of rock =?

Mass = Density × Volume

Mass of rock = 3.52 × 12

Mass of rock = 42.24 g

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