Question

2+x-(3-z); use x=6, and z=1​

Answer 1

Answer:

6

Step-by-step explanation:

$2+x-(3-z)\\ x=6\\ z=1\\= 2+6-(3-1)\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(3-1\right)\::\quad 2\\=2+6-2\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:2+6-2\:\\:\quad 6$

Answer 2

2+6-(3-1)
2+ 6-2
2+ 4
= 6