Answer: the options are not given, here are the options.
A. Cu2+/cu
b. Pb2+/Pb
c. Zn²+Izn
d. The potential for all three cells is the same.
The correct answer is A.
Cu2+/cu
Explanation:
A voltaic or galvanic cell is a cell that uses electrochemical energy generate from oxidation reduction reaction to produce electricity.
In this reaction manganese will be the anode and the Copper will be the cathode.
The half-cell reactions are given below and their respective cell potential.
Mn +Mn2+ + 2e- E°=-1.18v
Zn +2e=Zn E°=-0.76v
Pb+ +2r= Pb E° -0.13
Cu2+ + 2e= Cu E° 0.34
In solving the potential of the cell
E°cell= E° cathode -E°anode
For Mn and Cu.
(
s
)
+
Z
n
2
+
(
a
q
)
→
M
n
2
+
(
a
q
)
+
Z
n
(
s
)
E
∘
c
e
l
l
=
−
0.76
V
−
(
−
1.18
V
)
=
0.42
V
For Mn and Pb,
M
n
(
s
)
+
P
b
2
+
(
a
q
)
→
M
n
2
+
(
a
q
)
+
P
b
(
s
)
E
∘
c
e
l
l
=
−
0.13
V
−
(
−
1.18
V
)
=
1.05
V
For Mn and Cu,
0.34-(-1.18) = 1.52V.
Which happens to be the largest among the others.
