Question

The electron in the He+ ion is excited to the n = 2 principal state. What is the energy of the electron now?

Answer 1

Answer:

= -13.6 eV

Explanation:

E = -13.6 ÷ $\frac{Z^{2} }{n^{2} }$

where n is the principal state

Z is atomic number

and E is energy in electron volts.

Given that n = 2 and Helium Z = 2

⇒ E = -13.6 ÷ $\frac{2^{2} }{2^{2} }$

= -13.6 eV

I believe this is helpful and easy to follow.