Respuesta :

Here you are trying to find the hypotenuse. So you would take
5^2 (five squared) plus 12^2 (twelve squared) and add them using the equation a^2+b^2= c^2. Now you square 5 and 12 to get 25 and 144. You add them together and get 169. Take the square root of 169 and c. The square root on c will cancel out the squared (to the power of two) part leaving you with just c. And the square root of 169 is 13. So c (the missing length) is 13. C=13.

Answer:

[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{13 \: \: units \: }}}}}[/tex]

Step-by-step explanation:

Perpendicular ( p ) = 5

Base ( b ) = 12

Hypotenuse ( h ) = ?

Finding the length of missing side

Using Pythagoras theorem

[tex] \boxed{ \sf{ {h}^{2} = { p}^{2} + {b}^{2} }}[/tex]

plug the values

⇒[tex] \sf{ {h}^{2} = {5}^{2} + {12}^{2} }[/tex]

Evaluate the power

⇒[tex] \sf{ {h}^{2} = 25 + 144}[/tex]

Add the numbers : 25 and 144

⇒[tex] \sf{ {h}^{2} = 169}[/tex]

Squaring on both sides

⇒[tex] \sf{ \sqrt{ {h}^{2} } = \sqrt{169}} [/tex]

Calculate

⇒[tex] \sf{ {h} = 13 \: units}[/tex]

Hope I helped!

Best regards! :D

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