Answer:
When we are dividing exponents, there is this rule:
[tex]\frac{a^n}{a^m}=a^{(n-m)}[/tex]
So, in our case we have this:
[tex]\frac{16a^5b^3}{8ab} = \frac{16}{8}a^{(5-1)}b^{(3-1)}[/tex][tex]=2a^4b^2[/tex]
