Answer:
(d+9/2)(d-9/2)
Step-by-step explanation:
Use the formula. x=
[tex] + \sqrt({b { }^{2} } - 4ac) \div (2a) \ \\ - \sqrt({b { }^{2} } - 4ac) \div (2a) [/tex]
where x=d, a =1 , b=13 , c=22.
since,
[tex]ax {}^{2} + bx + c = 0[/tex]
