Mark incorrectly solved the inequality -4(5/2+3/2x) > 8. His work is shown. Which step shows an error based on the inequality ONLY from the previous step? Help please!!​

Mark incorrectly solved the inequality 45232x gt 8 His work is shown Which step shows an error based on the inequality ONLY from the previous step Help please class=

Respuesta :

Answer : The incorrect step is, (A) step 1: -10 + 6x > 8

Step-by-step explanation :

The given expression is:

[tex]-4(\frac{5}{2}+\frac{3}{2}x)>8[/tex]

Now solving this expression step by step.

First -4 distributed over parentheses.

[tex](-4\times \frac{5}{2})+(-4\times \frac{3}{2}x)>8[/tex]

Now solving bracket term, we get:

[tex]-10-6x>8[/tex]

Now taking like terms together, we get:

[tex]-6x>8+10[/tex]

[tex]-6x>18[/tex]

[tex]-x>3[/tex]

Now multiplying this expression by (-1), we get:

[tex]x>-3[/tex]

Thus, the incorrect step is, (A) step 1: -10 + 6x > 8

Answer:

A. Step 1: -10 + 6x > 8

Step-by-step explanation:

The correct way:

Step 1: Multiply both sides by [tex]-1[/tex] (reverse the inequality)

[tex]\left(-4\left(\frac{5}{2}+\frac{3}{2}x\right)\right)\left(-1\right)<8\left(-1\right)[/tex]

Step 2: Simplify

[tex]4\left(\frac{5}{2}+\frac{3}{2}x\right)<-8[/tex]

Step 3: Divide both sides by 4

[tex]\frac{4\left(\frac{5}{2}+\frac{3}{2}x\right)}{4}<\frac{-8}{4}[/tex]

Step 4: Simplify

[tex]\frac{5}{2}+\frac{3}{2}x<-2[/tex]

Step 5: Subtract [tex]\frac{5}{2}[/tex] from both sides

[tex]\frac{5}{2}+\frac{3}{2}x-\frac{5}{2}<-2-\frac{5}{2}[/tex]

Step 6: Simplify

[tex]\frac{3}{2}x<-\frac{9}{2}[/tex]

Step 7: Multiply both sides by 2

[tex]2\cdot \frac{3}{2}x<2\left(-\frac{9}{2}\right)[/tex]

Step 8: Simplify

[tex]3x<-9[/tex]

Step 9: Divide both sides by 3

[tex]\frac{3x}{3}<\frac{-9}{3}[/tex]

Step 10: Simplify

[tex]x<-3[/tex]

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