Answer:
The value is [tex]t = 3.28 \ s[/tex]
Explanation:
From the question we are told that
The initial velocity is [tex]u = 23.8 \ m/s[/tex]
The angle is [tex]\theta= 42.5^o[/tex]
Generally from the projectile motion equation we know that the time of flight is mathematically represented as
[tex]t = \frac{2 * u *sin (\theta )}{ g }[/tex]
=> [tex]t = \frac{ 2 * 23.8 * sin (42.5)}{9.8 }[/tex]
=> [tex]t = 3.28 \ s[/tex]