A football is kicked from ground level with an initial velocity of 23.8 m/s at angle of 42.5° above the horizontal. How long, in seconds, is the football in the air before it hits the ground? Ignore air resistance.

Respuesta :

Answer:

The  value  is   [tex]t = 3.28 \  s[/tex]

Explanation:

From the question we are told that    

      The  initial velocity is  [tex]u = 23.8 \  m/s[/tex]

       The angle is [tex]\theta=  42.5^o[/tex]

     

Generally from the projectile motion equation we know that the time of flight is mathematically represented as

       [tex]t  =  \frac{2 *  u  *sin (\theta )}{ g }[/tex]

=>    [tex]t =  \frac{ 2 *  23.8 *  sin (42.5)}{9.8 }[/tex]

=>      [tex]t = 3.28 \  s[/tex]

ACCESS MORE
EDU ACCESS