Answer:
d.f.(treatment) = 6
d.f.(error) = 35
Step-by-step explanation:
In the question we have
k = 7
r= 6
n= rk= 42
1. The degrees of freedom for the numerator is calculated as under
d.f.(treatment) = k-1= 7-1= 6
Where k gives the number of columns
2. The degrees of freedom for the denominator is calculated as under
d.f.(error) = k (r-1)= n-k= 42-7=35
where k gives the number of columns and r gives the number of rows.
This is for one way ANOVA as asked above.
