Respuesta :
Answer:
The adapted expression for average acceleration is [tex]a = \frac{v}{t'}[/tex].
Explanation:
Let be [tex]v = v_{o} + a\cdot t[/tex], which can be adapted by using the following substitution:
[tex]t = t'-t_{o}[/tex]
Where:
[tex]t'[/tex] - Final instant, measured in seconds.
[tex]t_{o}[/tex] - Initial instant, measured in seconds.
[tex]v = v_{o}+a\cdot (t-t_{o})[/tex]
Where:
[tex]v[/tex] - Final velocity, measured in meters per second.
[tex]v_{o}[/tex] - Initial velocity, measured in meters per second.
[tex]a[/tex] - Average acceleration, measured in meters per square second.
Now, average acceleration is cleared:
[tex]a = \frac{v-v_{o}}{t'-t_{o}}[/tex]
Given that [tex]t_{o} = 0\,s[/tex] and [tex]v_{o} = 0\,\frac{m}{s}[/tex], then:
[tex]a = \frac{v}{t'}[/tex]
Answer:
a = (v-v0)
____ where v = final velocity, v0
t
Explanation:
Using algebra, , where v = final velocity, v0 = initial velocity, and t = time. So,
= -9.3 m/s2.