contestada

Adapt the velocity equation v=v0 + at to solve for average acceleration where the ball starts at t = 0.0 seconds and v0 = 0.00 meters/second

Respuesta :

Answer:

The adapted expression for average acceleration is [tex]a = \frac{v}{t'}[/tex].

Explanation:

Let be [tex]v = v_{o} + a\cdot t[/tex], which can be adapted by using the following substitution:

[tex]t = t'-t_{o}[/tex]

Where:

[tex]t'[/tex] - Final instant, measured in seconds.

[tex]t_{o}[/tex] - Initial instant, measured in seconds.

[tex]v = v_{o}+a\cdot (t-t_{o})[/tex]

Where:

[tex]v[/tex] - Final velocity, measured in meters per second.

[tex]v_{o}[/tex] - Initial velocity, measured in meters per second.

[tex]a[/tex] - Average acceleration, measured in meters per square second.

Now, average acceleration is cleared:

[tex]a = \frac{v-v_{o}}{t'-t_{o}}[/tex]

Given that [tex]t_{o} = 0\,s[/tex] and [tex]v_{o} = 0\,\frac{m}{s}[/tex], then:

[tex]a = \frac{v}{t'}[/tex]

Answer:

a = (v-v0)      

     ____      where v = final velocity, v0

         t

Explanation:

Using algebra, , where v = final velocity, v0 = initial velocity, and t = time. So,

= -9.3 m/s2.

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