Question

The length of a rectangle is 2 m more than twice its width. Find the length and width of the rectangle, if its perimeter is 28 m.
Please use algebra.

Answer 1

Answer:

Length is 10

Width is 8

Step-by-step explanation:

The formula for the perimeter of a rectangle is:

$P=2l+2w$

We are told that the length l is 2 more than twice the width w. In other words:

$l=2+2w$

Also, we are given that the perimeter is 28. Therefore:

$P=2l+2w\\28=2(2+2w)+2w$

Distribute:

$28=4+4w+2w$

Combine like terms:

$28=4+6w$

Subtract 4 from both sides:

$6w=24$

Divide by 6:

$w=4$

So, the width is 4.

And the length is 2 more than twice the width. Thus:

$l=2+2(4)\\l=2+8=10$

The length is 10.

And we are done :)