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Question:

Carl throws a single die twice in a row. For the first throw, Carl rolled a 2; for the second throw he rolled a 4. What is the probability of rolling a 2 and then a 4? Answer choices are in the form of a percentage, rounded to the nearest whole number. O 22% 36% O 3% O 33%

Answer:

The probability of rolling a 2 then 4 is 3%

Step-by-step explanation:

Given

A die rolled twice

Required

Probability of rolling a 2 then 4; i.e. P(2 n 4)

First, we need to list out the sample space

[tex]S = \{1,2,3,4,5,6\}[/tex]

[tex]n(S) = 6[/tex]

Next, is to calculate P(2)

[tex]P(2) = \frac{n(2)}{n(S)}[/tex]

[tex]P(2) = \frac{1}{6}[/tex]

Next, is to calculate P(4)

[tex]P(4) = \frac{n(4)}{n(S)}[/tex]

[tex]P(4) = \frac{1}{6}[/tex]

Next,is to calculate the required probability using the following formula

[tex]P(2\ n\ 4) = P(2) * P(4)[/tex]

[tex]P(2\ n\ 4) = \frac{1}{6} * \frac{1}{6}[/tex]

[tex]P(2\ n\ 4) = \frac{1}{36}[/tex]

[tex]P(2\ n\ 4) = 0.02777777777[/tex]

Convert to Percentage

[tex]P(2\ n\ 4) = 2.777777777\%[/tex]

Approximate

[tex]P(2\ n\ 4) = 3\%[/tex]

Hence, the probability of rolling a 2 then 4 is 3%

Answer:

3%

Step-by-step explanation:

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