Answer:
66.8°
Explanation:
Calculating for tthe first leg
dNx = 0;
dNy = + 0.8 mi ......................(0 , 0.8)
then for the second
dWx = - 0.3 mi;
dWy = 0 ...................(-0.3 , 0)
then the third leg
dSx = 0;
dSy = - 0.1 mi ......................(0 , -0.1)
So the displacement vector is
db = ( -0.3 , (0.8 - 0.1) )
db = ( -0.3 , 0.7)
Finding the magnitude i= √(0.3^2 + 0.7^2 )
= 0.76
So the direction is
စ= tan^-1( 0.7 / 0.3 ) = 66.8°