Respuesta :
Answer:
The standard error is 0.033.
Step-by-step explanation:
We are given that Sukie interviewed 125 employees at her company and discovered that 21 of them planned to take an extended vacation next year.
Let [tex]\hat p[/tex] = proportion of employees who planned to take an extended vacation next year
[tex]\hat p[/tex] = [tex]\frac{X}{n}[/tex] = [tex]\frac{21}{125}[/tex] = 0.168
n = number of employees at her company = 125
Now, the standard error is calculated by the following formula;
Standard error, S.E. = [tex]\sqrt{\frac{\hat p(1-\hat p)}{n} }[/tex]
= [tex]\sqrt{\frac{0.168(1-0.168)}{125} }[/tex]
= [tex]\sqrt{\frac{0.168 \times 0.832}{125} }[/tex] = 0.033
Hence, the standard error is 0.033.
Answer:
.10 - .23
Step-by-step explanation:
.168 +/- 1.96 ( sqrt ((.168 * .832)/125))
