Question

I need help on this..... please ​

Answer 1

Answer:

$q(x)=2x-5,x\neq-2$

Step-by-step explanation:

So we have:

$a(x)=2x^2-x-10\\b(x)=x+2$

And we want to find the quotient q(x). Thus:

$q(x)=\frac{a(x)}{b(x)}$

Substitute:

$q(x)=\frac{2x^2-x-10}{x+2}$

Factor the numerator:

$2x^2-x-10\\=2x^2+4x-5x-10\\=2x(x+2)-5(x+2)\\=(2x-5)(x+2)$

Substitute:

$q(x)=\frac{(2x-5)(x+2)}{x+2}$

The (x+2)s cancel out. Therefore:

$q(x)=2x-5$

However, we must restrict x such that it cannot equal -2.

In the original equation, if it did, our answer would be undefined. Thus, our final answer is:

$q(x)=2x-5,x\neq-2$

And we are done :)

Edit: Typo