Question

A second number is 9 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 760, find the numbers. The three numbers are (Use a comma to separate answers as needed.)​

Answer 1

x = 1st number, 9x = 2nd number, x+100 = 3rd number
x + 9x + x + 100 = 760
11x = 760 - 100
11x/11= 660/11
X = 60
60 + 9(60) + 60 + 100 = 760